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Recitation 4B

Problem 1: Let T:R2R2T: \mathbb{R}^2\to\mathbb{R}^2 be the transformation that rotates each point in R2\mathbb{R}^2 about the origin through an angle ϕ\phi, with counterclockwise rotation for a positive angle. Assuming such a transformation is linear, find the standard matrix AA of this transformation.

Solution: It is enough to find T(e1),T(e2)T(e_1), T(e_2) where e1e_1 and e2e_2 are the columns of the identity matrix. According to the description of TT, we have T(e1)=(cosϕsinϕ),T(e2)=(sinϕcosϕ).T(e_1)=\begin{pmatrix}\cos\phi \\ \sin\phi\end{pmatrix}, T(e_2)=\begin{pmatrix}-\sin\phi \\ \cos\phi\end{pmatrix}. Therefore the standard matrix A=(T(e1)T(e2))=(cosϕsinϕsinϕcosϕ).A=\begin{pmatrix}T(e_1) & T(e_2)\end{pmatrix}=\begin{pmatrix}\cos\phi & -\sin\phi \\ \sin\phi & \cos\phi\end{pmatrix}.

Problem 2: Let TT be the linear transformation whose standard matrix is A=(148102130005)A=\begin{pmatrix}1 & -4 & 8 & 1\\ 0 & 2 & -1 & 3 \\ 0 & 0 & 0 & 5\end{pmatrix} Does TT maps R4\mathbb{R}^4 onto R3\mathbb{R}^3? Is TT a one-to-one mapping?

Solution: Because the standard matrix is already an echelon form with each row containing a pivot position, its columns span R3\mathbb{R}^3. In other words, TT maps R4\mathbb{R}^4 onto R3\mathbb{R}^3. On the other hand, since not every columns is a pivot column, Tx=0Tx=0 has a non-trivial solution. In other words, TT is not one-to-one.

Problem 3: Let T(x1,x2)=(3x1+x2,5x1+7x2,x1+3x2)T(x_1, x_2)=(3x_1+x_2,5x_1+7x_2, x_1+3x_2). Show that TT is a one-to-one linear transformation. Does TT map R2\mathbb{R}^2 onto R3\mathbb{R}^3?

Solution: First we shall find the standard matrix of TT. Let x1=1x_1=1 and x2=0x_2=0. We obtain T(e1)=T(10)=(351).T(e_1)=T \begin{pmatrix}1\\0\end{pmatrix}= \begin{pmatrix}3 \\ 5 \\ 1\end{pmatrix}. Let x1=0x_1=0 and x2=1x_2=1. We obtain T(e2)=T(01)=(173).T(e_2)=T \begin{pmatrix}0 \\ 1\end{pmatrix}= \begin{pmatrix}1 \\ 7 \\ 3\end{pmatrix}. Therefore the standard matrix of TT is A=(315713)A=\begin{pmatrix}3 & 1 \\ 5 & 7 \\ 1 & 3\end{pmatrix} Since the echelon form of AA contains two pivot columns, TT is one-to-one. On the other hand, since AA has three rows, not every row has a pivot position. Therefore TT does not map R2\mathbb{R}^2 onto R3\mathbb{R}^3. In general, a linear transformation never maps Rm\mathbb{R}^m onto Rn\mathbb{R}^n if m<nm < n.