Example 1: Evaluate ∫2x+1dx.
Solution: Let u=2x+1. Then ∫2x+1dx=∫u21du=31u3/2+C=31(2x+1)3/2+C.
Example 2: Find ∫1−4x2xdx.
Solution: Let u=1−4x2. Then ∫1−4x2xdx=−81∫u1=−81(2u)+C=−411−4x2+C.
Example 3: Calculate ∫e5xdx.
Solution: Let u=5x. then ∫e5xdx=51∫eudu=51eu+C=51e5x+C.
Problem 4: Evaluate ∫sec22θdθ.
Hint: Let u=2θ.
Problem 5: Evaluate ∫5−3xdx.
Hint: Let u=5−3x.
Problem 6: Evaluate ∫x(lnx)2dx.
Hint: Let u=lnx.
Problem 7: Evaluate ∫sec2θtan3θdθ.
Hint: Let u=tanθ.
Problem 8: Evaluate ∫ex1+exdx.
Hint: Let u=1+ex.
Problem 9: Evaluate ∫cotxcsc2xdx.
Hint: Let u=cotx.
Problem 10: Evaluate ∫1+x21+xdx.
Hint: Split the integral into ∫1+x21dx and ∫1+x2xdx. For the second integral, use substitution u=1+x2.
Problem 11: Evaluate ∫12x2e1/xdx.
Hint: Let u=1/x.
Problem 12: Evaluate ∫0axa2−x2dx.
Hint: Let u=a2−x2.
Problem 13: Evaluate ∫ee4xlnxdx.
Hint: Let u=lnx.