Example 1: Suppose ∑an and ∑bn are series with positive terms and (a) If an>bn for all n, what can you say about an? Why? (b) If an<bn for all n, what can you say about an? Why?
Answer: (a) If ∑bn diverges, so does ∑an. (b) If ∑bn converges, so does ∑an.
Problem 2: Determine whether the series is convergent or divergent? (a)∑n=1∞nnn+1; (b)∑n=1∞3+10n9n; (c)∑k=1∞1+k3ksin2k; (d)∑k=1∞(k+1)(k2+4)2(2k−1)(k2−1); (e)∑n=1∞3n−24n+1; (f)∑n=1∞n2+11; (g)∑n=1∞n!1; (h)∑n=1∞sin(1/n); (i)∑n=1∞n1+1/n1.
Hint: (a) Compare nnn+1 with 1/n; (b) Compare 3+10n9n with (9/10)n; (c) Use 1+k3ksin2k<1/k2; (d) Compare (k+1)(k2+4)2(2k−1)(k2−1) with 1/k3; (e) Compare 3n−24n+1 with (4/3)n; (f) Compare n2+11 with 1/n; (g) Use 1/n!<1/2n for all n>1; (h) Compare sin(1/n) with 1/n; (i) Compare 1/n1+1/n with 1/n and use limn→∞n1/n=1.