Example 1: Determine whether the series is convergent or divergent. If it is convergent, find its sum. (a) ∑2n1+3n; (b) ∑1+(2/3)n1; (c) ∑(3/5n+2/n).
Hint: (a) (b) Find the limit of an. (c) If ∑an is convergent and ∑bn is divergent, then ∑(an+bn) is divergent.
Example 2: Determine whether the series ∑n=1∞n(n+3)3 is convergent or divergent by expressing sn as a telescoping sum. If it is convergent, find its sum.
Hint: Note that k(k+3)3=k1−k+31. We have sn=∑k=1nk(k+3)3=∑k=1n(k1−k+31)=1/1+1/2+1/3−1/(n+1)−1/(n+2)−1/(n+3).
Example 3: Find the values of x for which the series ∑n=0∞(−4)n(x−5)n converges. find the sum of the series for those values of x.
Hint: This is a geometric series with initial term 1 and common ratio −4(x−5). It is convergent if and only if −1<−4(x−5)<1, i.e., 19/4<x<21/4. When it converges, the sum is 1/(1−(−4)(x−5))=1/(4x−19).
Example 4: Use the integral test to determine whether the series ∑n=1∞n2+1n is convergent or divergent.
Hint: Consider f(x)=x2+1x for x>1. Check it is continuous, positive and ultimately decreasing.
Example 5: Determine whether the series is convergent or divergent. (a) 1+1/8+1/27+1/64+1/125+…; (b) ∑n=1∞n2+41; (c) ∑n=2∞nlnn1.
Hint: Consider f(x)=1/x3, f(x)=x2+41, f(x)=xlnx1 for (a), (b), (c) respectively. Check they are continuous, positive and ultimately decreasing.